Percent of Americans Without Health Insurance by State, 2004–2006
Updated June 26, 2019 |
Infoplease Staff
State | 2004–2006 |
---|---|
Alabama | 14.1% |
Alaska | 16.7 |
Arizona | 19.0 |
Arkansas | 17.5 |
California | 18.5 |
Colorado | 16.6 |
Connecticut | 10.4 |
Delaware | 12.5 |
DC | 12.4 |
Florida | 20.3 |
Georgia | 17.6 |
Hawaii | 8.6 |
Idaho | 14.9 |
Illinois | 13.6 |
Indiana | 13.1 |
Iowa | 9.3 |
Kansas | 11.1 |
Kentucky | 13.8 |
Louisiana | 18.5 |
Maine | 9.5 |
Maryland | 13.5 |
Massachusetts | 10.3 |
Michigan | 10.6 |
Minnesota | 8.5 |
Mississippi | 18.1 |
Missouri | 12.3 |
Montana | 17.0 |
Nebraska | 11.1 |
Nevada | 18.3 |
New Hampshire | 10.4 |
New Jersey | 14.6 |
New Mexico | 21.0 |
New York | 13.2 |
North Carolina | 16.0 |
North Dakota | 11.1 |
Ohio | 10.7 |
Oklahoma | 18.7 |
Oregon | 16.6 |
Pennsylvania | 10.2 |
Rhode Island | 10.2 |
South Carolina | 16.0 |
South Dakota | 11.6 |
Tennessee | 13.4 |
Texas | 24.1 |
Utah | 15.7 |
Vermont | 10.8 |
Virginia | 13.2 |
Washington | 12.5 |
West Virginia | 15.5 |
Wisconsin | 9.4 |
Wyoming | 14.0 |
United States | 15.3 |
Source: U.S. Census Bureau, Current Population Survey, 2004 to 2006 Annual Social and Economic Supplements.
Health | Americans Without Health Insurance by Characteristic, 2005 |