Percent of Americans Without Health Insurance by State, 2013
Updated May 8, 2019 |
Infoplease Staff
The following table lists the percent of Americans who did not have health-insurance coverage in 2013. Data is listed by state.
State | 2013 |
---|---|
Alabama | 13.6% |
Alaska | 18.5 |
Arizona | 17.1 |
Arkansas | 16.0 |
California | 17.2 |
Colorado | 14.1 |
Connecticut | 9.4 |
Delaware | 9.1 |
DC | 6.7 |
Florida | 20.0 |
Georgia | 18.8 |
Hawaii | 6.7 |
Idaho | 16.2 |
Illinois | 12.7 |
Indiana | 14.0 |
Iowa | 8.1 |
Kansas | 12.3 |
Kentucky | 14.3 |
Louisiana | 16.6 |
Maine | 11.2 |
Maryland | 10.2 |
Massachusetts | 3.7 |
Michigan | 11.0 |
Minnesota | 8.2 |
Mississippi | 17.1 |
Missouri | 13.0 |
Montana | 16.5 |
Nebraska | 11.3 |
Nevada | 20.7 |
New Hampshire | 10.7 |
New Jersey | 13.2 |
New Mexico | 18.6 |
New York | 10.7 |
North Carolina | 15.6 |
North Dakota | 10.4 |
Ohio | 11.0 |
Oklahoma | 17.7 |
Oregon | 14.7 |
Pennsylvania | 9.7 |
Rhode Island | 11.6 |
South Carolina | 15.8 |
South Dakota | 11.3 |
Tennessee | 13.9 |
Texas | 22.1 |
Utah | 14.0 |
Vermont | 7.2 |
Virginia | 12.3 |
Washington | 14.0 |
West Virginia | 14.0 |
Wisconsin | 9.1 |
Wyoming | 16.6 |
United States | 14.5% |
Source: U.S. Census Bureau.
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